If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2(x+3)^2=128
We move all terms to the left:
2(x+3)^2-(128)=0
We move all terms containing x to the left, all other terms to the right
2(x+3)^2=128
| 2(x+3)2=128 | | 3=g+8/8 | | -2/5x=-3/5 | | m^2-5=-4 | | 3^2x-5=6 | | 37-8=32-n | | d/227=23 | | x+4/2=-x-14 | | 3/8x=-2/4 | | 2=1/2(11/2)h | | 4x+12+2x-6=90 | | f/2=103 | | ƒ(x)=x2–2x–24 | | z/10=26 | | 11/2=1/2(2)h | | c+16=88 | | -8+4/5p=12 | | p-2=97 | | (1/27)^4-x=3^2x-1 | | -4-2x=-8x+x^2 | | v/22=7 | | v-7.72=9.77 | | 2=1/2q-2 | | t/29=31 | | 1/4t=27/12 | | f+97.76=621.45 | | x+11-15;x=4 | | -5x=2x-9x+8 | | (6x+2)=x+(3x+1) | | n+17=8 | | 2x^2+4x=24 | | 4x+(5x-9)=90 |